Personal Details Query Reply
Name: Debajyoti Debbarma
Contact No.: 9402133702/8837342462
Email: ddebbarma391@gmail. com
State: Tripura
City: Agartala
Query Date: 03/02/2018
Arrange in increasing order of freezing point:- 0.01(M) KCl, 0.01(M) glucose, 0.01(M) NaCl Increasing order of freezing point among 0.01(M) KCl, 0.01(M) glucose, 0.01(M) NaCl is KCl greater than NaCl greater than Glucose Since maximum ions give minimum freezing point KCl is more ionic than NaCl, because in KCl, K's electronegativity is 0.82 and Cl's is 3.16. A compound is ionic when the electronegativity on the Pauling Scale is more than 2.1. The difference 2.34, so it is ionic.
Name: Rahul Das
Contact No.: 7005747979
Email: dasr87903@gmail.com
State: Tripura
City: Agartala
Query Date: 03/07/2019
Sir, I have no quer, today when u take class for TET,(03/07/19), and I know about yourself and go through your website, I just mad, sir, u taking TET classes, omg it's unbelievable, bt today class just osm osm, previous I know shortcut method or tricks about math, bt today u give us chemistry tricks, thank u for ur valuable time for us. Thanks and Carry on. Take my best wishes.
Name: Dipyaman Acharjee
Contact No.: 6009100153
Email: dipyamanacharjee@gmail.com
State: Tripura
City: Agartala
Query Date: 04/06/2019
Is there any exception between oxygen and sulfur in case of electron affinity? Oxygen has a lower electron affinity than Sulfur.This is likely due to second period elements' (O)being quite small, so electron-electron repulsion is much more significant than in a third period element (S).
Name: Somraj Biswas
Contact No.: 8131955134
Email: somrajb497@gmail.com
State: Tripura
City: Agartala
Query Date: 05/02/2018
Why is Iodine required in Mond's & Van Arkel's method? Why is is necessary to prepare a volatile compound in these methods? Van Arkel process is vapour phase refining in which when impure metal is heated with iodine vapour, the metal forms volatile metal iodide. The metal iodide vapour when heated over tungsten filament at high temperature pure metal is obtained by Van Arkel method. In this case, the metal should form a volatile compound with an available reagent because the volatile compound should be easily decomposable, so that the recovery is easy. (a) Monds Process for Refining Nickel • Nickel is heated in a stream of carbon monoxide forming a volatile complex, nickel tetracarbonyl. 330 – 350 K • Ni + 4CO → Ni(CO)4 • It is decomposed at high temperature giving the pure metal. 450 – 470 K • Ni(CO)4 → Ni + 4CO (b) Van Arkel Method for Refining Zirconium or Titanium • Useful for removing all the oxygen and nitrogen present in the form of impurity in certain metals like Zr and Ti. • The crude metal is heated in an evacuated vessel with iodine. The metal iodide being more covalent, volatilises: Zr + 2I2 → ZrI4 • The metal iodide is decomposed on a tungsten filament, electrically heated to about 1800K. The pure metal is thus deposited on the filament. ZrI4 → Zr + 2I2
Name: Somraj Biswas
Contact No.: 8131955134
Email: somrajb497@gmail.com
State: Tripura
City: Agartala
Query Date: 05/02/2018
I guess R-SH is less acidic than R-OH. Maybe due to presence of H bond R-OH is more acidic but come to talk about electron withdrawing effect? This problem should be solved with the help of H bond not with electron withdrawing effect i.e. (-I) effect. The solution is like that. Here, there is intermolecular H bond presents in alcohol molecules (-OH) which prevents liberation of H as proton and thus makes alcohol least acidic than that of thiol (-SH) where no such H bond present.
Name: Somraj Biswas
Contact No.: 8131955134
Email: somrajb497@gmail.com
State: Tripura
City: Agartala
Query Date: 05/02/2018
Is water ionic?Or covalent? Or both? Basically covalent but with ionic characters. How? Water (H2O) is a covalent compound. But as we know no compound is 100% ionic or 100% covalent. Since the electronegative difference (END) between hydrogen and oxygen is very high it is a strongly polarised covalent compound therefore the electron cloud is shifted towards the oxygen atom and therefore water has a very high % ionic character. Water is about 33% ionic.
Name: Debajyoti Debbarma
Contact No.: 9366203049
Email: ddebbarma391@gmail.com
State: Tripura
City: Agartala
Query Date: 05/09/2018
Why short chain fatty acids are not atherogenic Short chain fatty acids (SCFAs), a family of gut microbial metabolites, have been reported to promote preservation of endothelial function and thereby exert anti-atherogenic action. However, the precise mechanism mediating this protective action of SCFAs remains unknown. The research study investigated the effects of SCFAs (acetate, propionate and butyrate) on the activation of Nod-like receptor pyrin domain 3 (Nlrp3) inflammasome in endothelial cells (ECs) and associated carotid neointima formation.
Name: Debajyoti Debbarma
Contact No.: 9402133702/8837342462
Email: ddebbarma391@gmail. com
State: Tripura
City: Agartala
Query Date: 06/03/2018
Convert:- ethanol to 3-hydroxybutanoic acid see attachment

Name: Abhiraj roy
Contact No.: 9436580208
Email: Roysamhita@gmail.com
State: Tripura
City: Kamalpur
Query Date: 06/08/2018
Why does diagonal relationship not work with transition elements? In modern concept diagonal relationship is due to the similar polarising power of the ions. Polarising power = Charge (oxidation state) / ionic radius raised to the power 2, in transition series elements, they show variable oxidation state, hence do not show diagonal relationship.
Name: Litan Sarkar
Contact No.: 9876765443
Email: kjiuhjytgh@gmail.com
State: Tripura
City: Agartala
Query Date: 07/02/2018
What is the difference between ethene and ethane? Ethane is (organic compound uncountable) an aliphatic hydrocarbon, C2H6, gaseous at normal temperatures and pressures, being a constituent of natural gas while Ethene is (organic compound) the simplest alkene, a colorless gaseous (at room temperature and pressure) hydrocarbon with the chemical formula C2H4. Ethane is a saturated hydrocarbon. It has no single bonds where, Ethene is an saturated hydrocarbon. It has a double bond. The main difference between ethane and ethene is that the carbon atoms of ethane are sp3 hybridized (less electronegative - % S = 25%), whereas the carbon atoms in ethene are sp2 hybridized (more electronegative - % S = 33.3%). Thus ethene is more acidic than ethane
Name: Debajyoti Debbarma
Contact No.: 9366203049
Email: ddebbarma391@gmail.com
State: Tripura
City: Agartala
Query Date: 07/06/2019
Why reducing power of monosaccharide increases if taken in an alkaline medium? In alkaline medium, concentration of hydroxide increases, that will typically increase the reaction rate. Thus reducing power of monosaccharide increases if taken in an alkaline medium.
Name: prasanta das
Contact No.: 9402336606
Email: pasan.das.9402@gmail.com
State: Tripura
City: agartala
Query Date: 08/03/2018
Acidity order H-OH,R-OH,H2TE,H2S??? Acidic order is H2Te greater than H2S than H2O than R-OH. Due to +I effect of alkyl group in alcohol not in others and strength of H Bond increases with increasing electronegativity from Te to O which decreases acidic character from Te to O.
Name: prasanta das
Contact No.: 9402336606
Email: pasan.das.9402@gmail.com
State: Tripura
City: agartala
Query Date: 08/03/2018
if i ask any question how can i get my answer? To get ur answer Pl check reply against query menu in the free tutorial guide
Name: Rahul mog
Contact No.: 9774151124
Email: Rahulmog997@gmail.com
State: Tripura
City: Agartala,hapania
Query Date: 08/08/2018
1.what do you mean by the chiral and achiral?give example and explain both? Condition for Chirality for open chain compounds: 1.The compound must possess chiral centre 2.It does not contain any types of symmetry element namely plane of symmetry (Cv or Ch), centre of symmetry (Ci or i) etc. Eg. Meso tartaric acid contains horizontal plane of symmetry (Ch) is achiral (optically inactive). Optically active tartaric acid does not contain any symmetry element hence chiral.
Name: Sagardeep
Contact No.: 6009133927
Email: apuranisaha12@gmail.com
State: Tripura
City: Agartala
Query Date: 10/07/2019
The energy of an electron in the 3rd orbit of an atom is - E. The energy of an electron in the first orbit will be a) - 3E B)-E/3 C)-E/9 D)-9E Ans: D) -9E For Details solution see attached PDF File

Name: Sagar Singharoy
Contact No.: 9680280355
Email: chandansingharoy0@gmail.com
State: Tripura
City: Agartala
Query Date: 10/08/2018
Sir pls tell me how to find then factor for acid , base and salts and respective n factor in any reaction in your innovative way...apart from this I m also fascinated with your theory of hybridisation... Thank you... n factor calculation For Acids: Acids are the substances which furnish H+ ions when dissolved in a solvent. For acids, n-factor is defined as the number of moles of replaceable H+ atoms present in one mole of acid. For example, n-factor of HCI = 1, n-factor of HNO3 = 1, n-factor of H2SO4 = 1 or 2, depending upon extent of reaction it undergoes. H2SO4 + NaOH → NaHSO4 + H2O Although one mole of H2SO4 has 2 replaceable H atoms but in this reaction H2SO4 has only one H+ ion replaced by one Na+ ion, so its n-factor would be 1. H2SO4 + 2NaOH → Na2SO4 + 2H2O The n-factor of H2SO4 in this reaction would be 2. For Bases : Bases are the species, which furnish OH– ions when dissolved in a solvent. For bases, n-factor is defined as the number of moles of replaceable OH– ions present in 1 mole of base. For example, ● n-factor of NaOH = 1 ● n-factor of Zn(OH)2 = 1 or 2 ● n factor of Ca(OH)2 = 1 or 2 ● n factor of AI(OH)3= 1 or 2 or 3 ● n factor of NH4(OH) = 1 For Salts : Salts which react in a manner that only one atom undergoes change in oxidation state and goes only in one product. The n-factor of such salts is defined as the number of moles of electrons exchanged (lost or gained) by one mole of the salt.
Name: lisan sinha
Contact No.: 8415980608
Email: lisan15xinha@gmail.com
State: Tripura
City: Agartala
Query Date: 12/09/2018
1) Iso-propane never exists but Iso-butane exists-Explain. 2) Neo-butane never exists but Neo-pantane exists-Explain. 1. Iso group contains already 3 carbon atoms and its application will start from 4th carbon atoms hence Iso-propane never exists but Iso-butane exists. 2. Neo group contains already 4 carbon atoms and its application will start from 5th carbon atoms hence Neo-butane never exists but Neo-pentane exists.
Name: Aniruddha Das
Contact No.: 9089985595
Email: rajeshranjandas14@rediffmail.com
State: Tripura
City: Agartala
Query Date: 14/02/2018
Explain the water changes that occur when ice at 5degree centigrade is converted to water at 100 degree centigrade Water is a very common substance here on Earth. Water can change into three phases of matter (solid, liquid and steam). Water is most common in its liquid state when it is kept a normal pressure and between 0 degree Celsius and 100 degree Celsius. Water turns to ice as its solid state from 0 degrees Celsius and below. Water turns into steam from 100 degrees and above.
Name: Aniruddha Das
Contact No.: 9089985595
Email: rajeshranjandas14@rediffmail.com
State: Tripura
City: Agartala
Query Date: 14/02/2018
Define water of crystallization The water present in the crystals of the salts of certain metals; it is weakly bound by electrostatic forces and may normally be removed by heating. So, shortly, water of crystallization is defined as water that comes from a crystal substance after heat is applied at 100°C (212°F), results in a change in the crystalline structure.
Name: Aniruddha Das
Contact No.: 9089985595
Email: rajeshranjandas14@rediffmail.com
State: Tripura
City: Agartala
Query Date: 14/02/2018
Distinguish between deliquescence and efflorescence Efflorescence: When some substances are exposed to air, they lose water to the atmosphere, thereby reducing in weight. Solids that behave in this way are those with water of crystallization. The molecules of water of crystallization are partially or completely lost to the atmosphere, thereby making them lose their crystalline forms. Example: Na2SO4. 10H2O loses all its water of crystallization when exposed to air; Na2CO3. 10H2O loses 9 of its molecules of water of crystallization; and FeSO4. 7H2O loses all its molecules of water of crystallization. Deliquescence: This is when certain solid substances, when exposed to air absorb water, enough to form solutions. Example: CaCl2 and P4O10 can be used to dry gases (Substances which absorb water from air can be used as drying agents for gases), but not ammonia. Conc. H2SO4 is used to dry HCl. CaO or silica gel is suitable for drying ammonia gas, this is because CaCl2 , P4O10 and H2SO4 will react with the ammonia.
Name: Aniruddha Das
Contact No.: 9089985595
Email: rajeshranjandas14@rediffmail.com
State: Tripura
City: Agartala
Query Date: 14/02/2018
Distinguish between dissociation and ionization Ionization is the production of new ions by gain or loss of electron whereas dissociation is the split or separation of ions which already exist in a compound.
Name: Aniruddha Das
Contact No.: 9089985595
Email: rajeshranjandas14@rediffmail.com
State: Tripura
City: Agartala
Query Date: 14/02/2018
Compare Nacl And CsCl with respect to ease of formation of ionic bond Ionic compounds are formed easily between larger cation and smaller anion. Formation of ionic bond in CsCl is easier than NaCl due to larger size/radius of Cs+ than that of Na+ becoz in both the cases anion be same as chloride ion (Cl-). Thus the strength of ionic bond in NaCl is more than CsCl.
Name: Aniruddha Das
Contact No.: 9089985595
Email: rajeshranjandas14@rediffmail.com
State: Tripura
City: Agartala
Query Date: 14/02/2018
Carbon combines with oxygen to form 2 oxides. The carbon content of one of the oxides is 42.9 percent and the other is 27.3 %. Show that the data is in agreement with multiple proportion Step 1: To calculate the percentage composition of carbon and oxygen in each of the two oxides In First oxide: C-42.9% & O-57.1% and in Second oxide C-27.3% & O-72.7% Step 2: To calculate the weights of carbon which combine with a fixed weight i.e., one part by weight of oxygen in each of the two oxides. In the first oxide, 57.1 parts by weight of oxygen combine with carbon = 42.9 parts. 1 part by weight of oxygen will combine with carbon In the second oxide 72.7 parts by weight of oxygen combine with carbon = 27.3 parts. 1 part by weight of oxygen will combine with carbon Step 3: To compare the weights of carbon which combine with the same weight of oxygen in both the oxides- The ratio of the weights of carbon that combine with the same weight of oxygen (1 part) is 0.751: 0.376 or 2:1 since this is a simple whole number ratio, so the above data illustrate the law of multiple proportions.
Name: Debadatta Bhattacharya
Contact No.: 7005320595
Email: debadattabhattacharya93@gmail.com
State: Tripura
City: Agartala
Query Date: 14/06/2019
Sir , we know that the periodic trends of electropositivity increases if we move from top to bottom then the element Francium should have highest electropositivity but we consider caseium as highest eleelectropositive element why is so ? The alkali metals are the most electropositive. Cesium (Cs) is the most electropositive of the stable elements. Atomic no (Z)=55. Actually, Francium is more electropositive (at least in theory) but only about 30 grams exists on the entire planet as it is highly radioactive, unstable and decays readily.It is not available to us in its elementary form to measure its electropositivity.
Name: Anupam Debnath
Contact No.: 9862555681
Email: danupam66@gmail.com
State: Tripura
City: Ambassa
Query Date: 15/03/2018
Which of the following configuration is expected to have maximum difference in 2nd & 3rd ionisation enthalpies ? And why? 1) 1s2 2s2 2p2 2) 1s2 2s2 2p6 3s1 3) 1s2 2s2 2p6 3s2 4) 1s2 2s2 2p1 And: 3 [Mg2+ 3s0 (Ne): IE3 & Mg+ (3s1): IE2]
Name: George Halam
Contact No.: 8794830162
Email: Georgehalam73@gmail.com
State: Tripura
City: Agartala
Query Date: 15/04/2018
Sir can you explain the bond order of NO3- and NO2- with your innovative method Ya. Bond order of oxide based acid radical = valency of Peripheral atom - charge / total no of O atoms. For NO3- b.o. = 2 - 1/3 = 5/3 = 1.66 and for NO2- b.o. = 2 - 1/2 = 3/2 = 1.55.
Name: Nirupam Nath
Contact No.: 8132046162
Email: nathnirupam252017@gmail.com
State: Tripura
City: Agartala
Query Date: 19/04/2019
What will be the hybridisation state and number of unpaid electron in the compound [Ni (NH3)6]Cl2 .. [Ni (NH3)6]Cl2, is an outer orbital octahedral geometry having sp3d2 hybridization and two (n=2) unpaired electrons.
Name: Aniruddha Das
Contact No.: 9089985595
Email: rajeshranjandas14@rediffmail.com
State:
City:
Query Date: 20/01/2018
What is bertholoid compound Bertholoid compounds (Fe3O4) having an FeO-content of from 0 to 30%
Name: Satarupini
Contact No.: 7055403082
Email: bijayapaul76@gmail.com
State:
City:
Query Date: 21/01/2018
What is hyperconjugation? Hyperconjugation involves delocalization of sigma electrons
Name: Debajyoti Debbarma
Contact No.: 9402133702/8837342462
Email: ddebbarma391@gmail. com
State:
City:
Query Date: 21/01/2018
(1)Why xenonoxyfluoride cant't be stored in glass vessel? (2)Example of neutral flux? (1)Why xenonoxyfluoride cant't be stored in glass vessel? It cannot be stored in glass or quartz vessels because it reacts with silica of the glass and give the dangerously explosive xenon trioxide. (2) Neutral fluxes contain alumina or calcium fluoride and include clay, bauxites, crushed firebrick, and fluorspar.
Name: Debajyoti Debbarma
Contact No.: 9402133702/8837342462
Email: ddebbarma391@gmail. com
State:
City:
Query Date: 21/01/2018
why effective nuclear charge remains constant as we move from top to bottom in periodic table? The periodic table trends for effective nuclear charge: 1.Increase across a period (due to increasing nuclear charge with no accompanying increase in shielding effect). 2.Decrease down a group (although nuclear charge increases down a group, shielding effect more than counters its effect).
Name: Sudipta Choudhury
Contact No.: 7005661851
Email: mithi5799@gmail.com
State:
City:
Query Date: 23/01/2018
Give reason : SN1 reaction are accompanied by racemization in optically active alkyl halides. (For 3 marks) SN1 reaction occurs in two steps. In the first step there is a formation of carbocation (Carbonium ion) as an intermediate takes place. This carbocation has sp2-hybridised and planar structure. In the second step this planar carbocation is attacked by nucleophile (Nu-) from both the sides equally (Attack of Nu- from Front Side - Retention of Configuration occurs and Attack from Back Side - Inversion of Configuration occurs) to form d or (+) and l or (-) isomers in equal proportion i.e. enantiomeric pair. Such products are called racemic mixture. Hence, SN1 reaction are accompanied by racemization in optically active alkyl halides.
Name: Souvik Saha
Contact No.: 9774384710
Email: saha.anjan1963@gmail.com
State: Tripura
City: Agartala
Query Date: 23/11/2018
1} Does Riemann Riemann reaction occur in pyrolle? Products please. 2} Cr(H2O)6, is it inner or outer orbital complex? 1.The Riemer Tiemann reaction is a chemical reaction used for the ortho-formylation of phenols; with the simplest example being the conversion of phenol to salicylaldehyde. When phenols are treated with chloroform in the presence of sodium hydroxide, an aldehyde group (-CHO) is introduced at the ortho position of benzene ring leading to the formation of o-hydroxybenzaldehyde. This reaction is popularly known as Reimer Tiemann reaction. Electron rich heterocycles such as pyrroles and indoles are also known to react in the Riemann Riemann reaction. The reaction needs heat to initiate the process. However, once the reaction is begun, it can prove to be highly exothermic and further increase the reaction rate. The ring-expansion products, namely, chloropyridine would result when pyrrole subjected to Reimer–Tiemann reaction. 2.Cr(H2O)6,is an outer orbital octahedral complex (n=4) having sp3d2 hybridization.
Name: Saptarshi Das
Contact No.: 9366068149
Email: dsaptarshi32@gmail.com
State: Tripura
City: Agaratala
Query Date: 24/06/2018
What are the two examples of isoster? Isoster are atoms, molecules, or ions of similar size containing the same number of atoms and valence electrons. eg. O2- is an isoster of Ne and F-.
Name: Shreya Ghosh
Contact No.: 7059934935
Email: sghosh@gmail.com
State: West Bengal
City: Kolkata
Query Date: 25/02/2018
Which one has higher boiling point in between 2-methyl pentane and 3-methyl pentane ? Both having same molecular weight and branching but due to symmetric nature of 3-methyl pentane ( can be divided into two equal halves) it has higher boiling point than 2-methyl pentane.
Name: Biplab Saha
Contact No.: 7005731818
Email: biplabbeck74@gmail.com
State: Tripura
City: Agartala
Query Date: 26/07/2018
sir, power of hybridization (P)= (total no of sigma bond - 1). it is applicable upto 4 sigma.But for 5,6,7,8....th sigma how to find P? In case of sp3d, sp3d2 and sp3d3 hybridization state there is a common term sp3 for which four (04) TSLP is responsible. So, with four (04) TSLP, for each additional TSLP (additional sigma bond or lone pair of electron), added one d orbital gradually as follows:- 5 TSLP = 4 TSLP + 1 additional TSLP = sp3d hybridization 6 TSLP = 4 TSLP + 2 additional TSLP = sp3d2 hybridization 7 TSLP = 4 TSLP + 3 additional TSLP = sp3d3 hybridization Here, TSLP = (Total no of σ bonds around each central atom + LP)
Name: Arijoy Bhattacharjee
Contact No.: 9862208789
Email: arijoy06@gmail.com
State: Tripura
City: Agartala
Query Date: 28/03/2018
Boiling Point of benzene, Aniline,methanol, and nitrobenzene are 80dC,184dC,65dC, and 212dC (dC- degree celcius) respectively. Which has highest Vapour Pressure at room Temperature? Boiling point is inversely proportional to Vapour pressure. With increasing BP, VP decreases.
Name: Arnab Bose
Contact No.: 9436541034
Email: hiimab04@gmail.com
State: Tripura
City: Agartala
Query Date: 29/01/2018
The pH of a 0.1 molar solution of the acid HQ is 3.The value of the ionisation constant K(a) of the acid is ? HQ = H+ + Q- Initial Conc. 0.1M(HQ) 0(H+) 0(Q-) pH = 3 therefore, [H+] = 10-3 at equilibrium { pH = - log [H+] = - log (10-3) = 3 log10 = 3 } At Equilibrium [H+] = [Q-] = 10-3M Hence, [HQ] = 0.1M – 10-3 M = 0.1M Ka for the above reaction is given by Ka = [H+] [Q-] / [HQ] = [10-3] [10-3] / [0.1] = 10-5
Name: Arijoy Bhattacharjee
Contact No.: 9862208789
Email: arijoy06@gmail.com
State: Tripura
City: Agartala
Query Date: 29/03/2018
1. What is isotone? 2. Relationship between number of photon, wavelength and Energy- What is the number of photons of light of wavelength 7000 Armstrong equivalent to 1J? i) Isotone: Two nuclides are isotones if they have the same neutron number N, but different proton number Z. Eg.Boron-12 and Carbon-13 nuclei both contain 7 neutrons, and so are isotones. ii) ii) They are related by λ = hc/ Ephoton where, h = Plank's constant, c = velocity of light and λ = wavelength of the photon. iii) 1A = 10-10m, λ = 7000A = 7.0x10-7 m Energy of each photon is given by Planck's equation E = hc/λ; Let N = number of photons, Here E = 1.0J; N x (hc/λ) = 1.0 J; N = λ/hc = 7.0 x 10-7 / (6.625 x 10-34 x 3.0 x 108 m/s); N = 3.52 x10-18